Hi lmrzd,
Pins 4 and 5 will be connected to the current sensor, in this case the shunt. The shunt will have 3 terminals on it, two terminals across which the voltage drop is measured, these two inputs will go to V1P and V1N, with V1P on the side of the shunt that goes to the load. Then the third lead on the shunt is the gnd reference and should be connected to GND of the ADE7753. Note: this means that the ADE7753 is floating at the line voltage, if you want to avoid this then place the shunt after the load so that it is on the Neutral of your 5 to 10 V system.
The pins 6 and 7 will be connected to the voltage divider. Then the voltage divider will then be set up as shown in Figure 30 of the Data Sheet. The voltage divider will be set up to give a +/- 0.250 V peak output across the smaller resistor (1kOhm) of the voltage divider. Pay attention to what you have as the GND from the setup of the shunt mentioned above, because that will decide how the resistor divider is setup to keep from putting more that 0.500 V peak on the input pin.
Just to double check, is this an AC system?
Regards,
Dlath